imposter syndrome

inch The topic describing TCP ' s Maximum Segment Size (MSS) parameter , I explained the trade-off in determining the optimal size of TCP segments. If segments is too large, we risk have them become fragmented at the IP level. Too small, and we get greatly reduced performance because we is sending a small amount of data in a segment with at least bytes of header overhead. We also use up valuable processing time, which is required to handle, each of these small segments. The MSS parameter ensures

;}----------------------------------------------------------------------- 3668: [Noi2014] Get up difficulty syndrome Time Limit:Ten Sec Memory Limit:Mb Submit:1054 Solved:596 [Submit] [Status] [Discuss] Description 21st century, many people have a strange disease: Get up difficulty syndrome, its clinical manifestations are: Get up hard, get up after the bad spirit. As a young sunshine

From high to low enumeration expected should be the ans highest bit as far as possible to take one. If the number of the highest bit is O, you can get 1 direct update ans Otherwise determine if the bit 1 will burst m will not be added.#include 3668: [Noi2014] Get up difficulty syndrome time limit:10 Sec Memory limit:512 MBsubmit:1755 solved:962[Submit] [Status] [Discuss] Description21st century, many people have a strange disease: Ge

Description21st century, many people have a strange disease: Get up difficulty syndrome, its clinical manifestations are: Get up hard, get up after the bad spirit. As a young sunshine good teenager, ATM has been insisting on the struggle against getting out of trouble syndrome. By studying the relevant literature, he found the cause of the disease: in the depths of the Pacific Ocean, there is a dragon named

I was reading a book the other day. ProgramClerk, which mentioned that some programmers had second language syndrome-it was easy to learn the third and fourth languages, but the second language would have killed them. At that time, I was sure that I had this problem, because I had always wanted to know the Java language, but I was reluctant to start. I had never known why it was so difficult to start. Now I am suddenly enlightened. Soon after I read

People with progressive delusion syndrome, one of their biggest traits is the ability to be self-satisfied, unsatisfied with the current state, and easily overestimate their abilities. They are not very awake in their ability to look at themselves, do not go all out in doing things, but donuts, it is difficult to obtain deep-seated development. At the same time, they want others to their own requirements lower the better, so often for their imperfecti

Tell you the program apes are a cruel fact-the holidays are over! Are you still lying in bed and don't you want to get up? Get up quickly! Think about not debugging the good bug, think of the owners who want to be dissatisfied, these will let you sober point?Well, I am honest, small make up now also in the quilt hair strum it ~ do not ask why I do not get up, the following figure will tell you the answer.This is the clinical manifestation of the small-section

This concept is a bit interesting. It can be seen in an English document. It seems that the old Chinese and old Chinese are all the same, and it is easy to get lost on the journey. It will be awakened only when the deadline is reached. Back to the truth, everyone should have similar experiences at school. at ordinary times, it seems that no one is in a hurry. At the time of the exam, many people will suddenly find that there are still many things that have not been learned well, so I quickly wo

First of all, I would like to pay tribute to my colleagues who are still working in their posts and those who have returned home without having to brush up on the blog garden.I recently read The "The Clean Coder", but an unexpected result is that I knew there was still a "tomato working method ". I tried it for a few days and thought it was very effective. I recommend it to you.XX work method, once you hear this name, you can guess that it is time management, and time management is often equival

is different, and one of the reasons for vertigo. ==> Read the original4. in order to avoid the VR dizziness this thing, all the VR team have a heart VR is divided into Visual movement syndrome and simulated motion sickness . to solve the simulated motion sickness, The essential way is to make your body really move. Infinite Space solution: The only solution to the current VR infinite space solution is the Univer

Bitwise enumeration from high to low, greedy. If the bit fill 1 than fill 0 result excellent and fill 1 will not exceed the M limit, then fill 1, otherwise fill 01 /*by Silvern*/2#include 3#include 4#include 5#include 6 using namespacestd;7 Const intmxn=100020;8 intn,m;9 intp[ *];Ten intOP[MXN],A[MXN]; One intans=0; A intProintx) { - for(intI=1; i){ - if(op[i]==1) x=xA[i]; the Else if(op[i]==2) x=x|A[i]; - Elsex=x^A[i]; - } - returnx; + } - intMain () { +sca

);Const DoubleEPS = 1e-8;Const intMoD = 1e9+7;Const intINF =1061109567;Const intdir[][2] = { {-1,0}, {1,0}, {0, -1}, {0,1} };intM, ans, N, digit[100005][ +];Charc[100005][4];voidCalintNumintflag) { intx =0; for(inti =0; i) { if(c[i][0] =='A') {x=Digit[i][num]; } Else if(c[i][0] =='O') {x|=Digit[i][num]; } Else{x^=Digit[i][num]; } } if(x) {ans+= (1num); return ; } if(flag) {x=1; for(inti =0; i) { if(c[i][0] =='A') {x=Digit[i][num]; } Else if(c[i][0] =='O') {x|=Digi

Test instructions: It's better to understand.Analysis: Invert each word, build a dictionary tree, and then violently match the encrypted stringNote: Then I just don't understand, the above kind can, and the time is very short, but I think vice versa.The first I wrote was to reverse the cipher string, and then the word was built into the dictionary tree, and then it was tle, and it could have been written backwards.Really baffled, and then I guess the number of words is probably less#include #inc

BZOJ3668[NOI2014] getting up difficulty syndromeTest instructionsAsk for a number from 0 to M, so that it is the largest after n operations. Operation three kinds: t, |t, ^t,t for the given number in the operation. n≤100000,m,t≤1000000000ExercisesFirst find out the number of 0 after n operations, and then for each bits less than or equal to M from big to small consider if this is 1 is better than 0, if good to make this 1 and let M minus this bits. Because the bits of 1 after n operations is as

; }}intMain () {scanf("%d%d", n, m); for(inti =1; I scanf('%s ', DOOR[I].S);scanf("%d", door[i].num); } init ();intAns =0;intTMP =0; for(inti = to; I >=1; i--) {intX1 =0, x2 = bit[i];//x1, 0, x2, 1; for(intj =1; J if(door[j].s[0]==' A ') {x1 = (door[j].numbit[i]); X2 = (door[j].numbit[i]); }Else if(door[j].s[0]==' X ') {x1 ^= (door[j].numbit[i]); X2 ^= (door[j].numbit[i]); }Else{x1 |= (door[j].numbit[i]); X2 |= (door[j].numbit[i]); } }if(x1) {ans |

As the old saying goes, foreign affairs do not ask Google, the internal matter do not feel asked Baidu. Since Google's exit from China, Baidu has become almost the only option (forgive my disregard for other search engines). I and my colleagues and friends, the same problems, like the first time to Baidu search answers, unconsciously formed a serious dependence. Especially our technical staff, often encountered problems, immediately Baidu, immediately found the answer, can save a lot of time. Ho